Re: Problem with my split routine I am not understanding
- From: Jeremy <my-first-name@xxxxxxxxxx>
- Date: 28 Dec 2006 18:45:09 GMT
On Thu, 28 Dec 2006 10:30:01 -0800, Beliavsky wrote:
integer :: bpos = 1, pos = 1, idx = 1
I have not read your message carefully, but do you realize that the
line above is equivalent to
integer, save :: bpos = 1, pos = 1, idx = 1
I did not realize that. Your solution of not initializing bpos, pos and
idx in that manner fixed the problem. Thank you for the pointer.
Jeremy
.
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- From: Jeremy
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- From: Beliavsky
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