Re: communicating the name of a function to deep within the call tree

Phillip Helbig---remove CLOTHES to reply
<helbig@xxxxxxxxxxxxxxxxxxxxxxxx> wrote:

(I personally don't
see why 1/3*VAR1/VAR2*VAR3**VAR4 shouldn't give the same result. I
agree that 1/3 as a standalone expression should give 0.)

See numerous previous posts about why Fortran does not evaluate
expressions depending on context. It does not matter whether it is a
standalone expression or part of something else; 1/3 always means the
same thing. Making it depend on context would completely tear apart the
core of expression parsing, and would result in great confusion in
complicated cases.

--
Richard Maine | Good judgement comes from experience;
email: last name at domain . net | experience comes from bad judgement.
domain: summertriangle | -- Mark Twain
.