Re: allocating arrays, trouble


"Arjen Markus" <arjen.markus@xxxxxxxxxx> wrote in message
news:f2583e1d-5dd5-432d-80e4-b54b38673971@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
On 26 nov, 11:38, "Förster vom Silberwald" <chain_l...@xxxxxxxxxxx>
wrote:
On Nov 26, 10:26 am, "Wade Ward" <w...@xxxxxxxxxxx> wrote:

real*8, dimension(buff1,buff2) :: ger2

Why the non-portable declaration? Would it work with silverfoerster 95?

Why is it non-portable? What do you mean by silverfoerster 95?

Thanks

"real*8" is a (popular) extension to the FORTRAN 77 standard
for:

double precision

(The "8" refers to the fact that on many machine double
precision reals are implemented with 8 bytes. But that
is not guaranteed.)

Current F90/95/... practice is this:

real(kind=kind(1.0d00))
^^^^^^^^^^^ whoops, mpj

(or any of a variety of means to determine the kind of
double precision reals).
If you've taken precautions to portablt get yourself to dp, what do you have
to do to get to quad p?

Danke im voraus,
--
wade ward

wade@xxxxxxxxxxx
435 -838-7760



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