Re: allocating arrays, trouble

To repeat, you did not declare the variable, as you misspelled it.

Michael


In article <13e70ff2-e276-428a-8ec6-8258be941aa5@xxxxxxxxxxxxxxxxxxxxxxxxxxx>,
chain_lube@xxxxxxxxxxx says...

On Nov 26, 2:21 pm, Arjen Markus <arjen.mar...@xxxxxxxxxx> wrote:
On 26 nov, 14:59, Reinhold Bader <Ba...@xxxxxx> wrote:



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F=F6rster vom Silberwald wrote:

[snip]

PS: However, still I am interested in my original question: why can't
I pass buffer integer variables to a subroutine so as to allocate an
array and memory? Is this due to my ifort compiler?

ifort puts automatics on the stack. There are two workarounds: Either

* increase your stack limit (e.g., via the "ulimit -s ..." command) in y=
our
shell before running a.out
* use the -heap-arrays switch supported by newer ifort (9.1+) releases.

Regards
Reinhold

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Well, actually there is another one:

Explicitly allocate the arrays you need at the start.

BTW, Steve Lionel posted a link the other day to a series
of articles that expose some of the finer details of Fortran.
One of these concerns the use of the stack. I recommend
reading it.

Regards,

Arjen


Thanks for all the tips (I really appreciate it). But still I do not
get it: what is the difference between passing a buffer variable
(which actually holds the dimension!) and hard coding the dimension
into the declare statement?

Is this a compiler issue or just prohibited in Fortran 90?

Thanks

.

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