Re: Rounding off double precision

From: Bamm <bammster@xxxxxxxxx>
Date: Mon, 31 Mar 2008 05:46:41 -0700 (PDT)

For Fortran 77 define Floor as:
DINT(X)=X-DMOD(X,1.D0)
FLOOR(X)=DINT(X)-DMOD(2.D0+DSIGN(1.D0,X),3.D0)

What is DMOD and DINT, and how are they different from MOD and INT?
Thanks.

Btw, the problem has been solved. But I am looking at your suggestion
as it might lead to something better.
.

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