Re: Rounding off double precision

On Mon, 31 Mar 2008 05:46:41 -0700 (PDT), Bamm <bammster@xxxxxxxxx> wrote:

-|> For Fortran 77 define Floor as:
-|> DINT(X)=X-DMOD(X,1.D0)
-|> FLOOR(X)=DINT(X)-DMOD(2.D0+DSIGN(1.D0,X),3.D0)
-|
-|What is DMOD and DINT, and how are they different from MOD and INT?
-|Thanks.
These force Double Precision versions of MOD and AINT to be used.
-|
-|Btw, the problem has been solved. But I am looking at your suggestion
-|as it might lead to something better.

.

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