Re: Rounding off double precision

Sigh. The text you quoted above reads "creates a literal constant
with the double-precision value". The literal constant is
"3.141592653589793238d0" and is a double precision value. The fact
that it is being assigned to a single-precision parameter is something
different. A parameter is not a literal constant and vice-versa.

So how do you declare a constant in Fortran? I thought parameter was
the way constants were defined in Fortran, but if there is a better
way, I'd like to try it.
.

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