Re: Integers and standard

Steven G. Kargl wrote:
Note, it does not use signed-int-literal-constant. More importantly
Z'80000000' will be converted to either an INTEGER(8) or INTEGER(16)
(depends on the hardware and I'm using gfortran's kind type parameter
values) value prior to the assignment.


data i/Z'80000000'/
Error: Arithmetic overflow converting INTEGER(16) to INTEGER(4) at (1)

I don't have gfortran installed, so I can't test it, but what does
it do if you overflow an integer expression at run-time? If
it doesn't abort then, why does it cause fatal error at compile-
time? The standard doesn't say what implementations should
do with overflow, but whatever it is should be consistent as
a quality of implementation issue.

J. Giles

"I conclude that there are two ways of constructing a software
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