Cube root results in integer only...

From: christopher.j.denver@xxxxxxxxxxxxxx
Date: Wed, 19 Nov 2008 03:52:40 -0800 (PST)

Hi newsgroup,

I'm using a fortran compiler within Aspen Plus 2006.5 - sorry but I
don't really know which Fortran this software uses...

When I try to receive a cube root from this statement:

PI = ACOS(-1)
MM = PI ** (1./3.)

I always get MM = 1 instead of the result I wanted (1.46459...)

Does anyone know why this might be the reason? It seems like the
statement is somehow truncated, as for a real number such as 1.6995
the result is also shown as 1, whereas for 2.5865 it is shown as 2
etc...

Thanks a lot and best regards,

Christopher
.

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