Re: embedded questions!!!

On Fri, 13 Jan 2006 19:18:53 GMT in comp.arch.embedded, Jonathan
Kirwan <jkirwan@xxxxxxxxxxxxxx> wrote:

>On Fri, 13 Jan 2006 10:47:45 -0600, Dave Hansen <iddw@xxxxxxxxxxx>
>wrote:
>
>>"a[i]" has *exactly* the same meaning as "(*a + i)" whether a is a
>>pointer or array.
>
>You mean *((a)+(i)). Or perhaps more precisely, to capture usual

Actually, I meant "*(a + i)". Apologies for fat-fingering that. I
think, however, the additional parentheses in *((a)+(i)) are
redundant, at least if a[i] is a well-formed expression.

>unary conversion rules, *((&a[0])+(i)).

Well, no, actually, that's not necessary, and arguably wrong. Consider
i[a], which should be equivalent to a[i].

Regards,
-=Dave

--
Change is inevitable, progress is not.
.

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