Invoking a function through function pointer

Respected Experts,
Iam Ravikumar.N, I have a query regarding
pointer to a function. I have a sample code, it is as follows


void func(int x, int y)
{
cout << x << "\n";
cout << y << "\n";
}


void main()
{
void (*fp)(int, int);

fp = func;
(*fp)(10, 20); //One way of invoking the function
fp(10, 20); //Another way of invoking the function
}

The above code reveals that the function "func" can be invoked in
two ways

i.e. 1)(*fp)(10, 20);
2) fp(10, 20);

I would like to know what is the difference between in these two
invocations.

With Regards
Ravi Kumar.N
.

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