Re: Mathematical models for loop calculations
- From: Richard Heathfield <rjh@xxxxxxxxxxxxxxx>
- Date: Wed, 26 Sep 2007 13:51:58 +0000
Richard Heathfield said:
<snip>
d = I * (I + 1) /2 + 1;
Er, of course I meant d = (I + 1) * (I + 2) / 2 + 1;
--
Richard Heathfield <http://www.cpax.org.uk>
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