Precision on size int in C...
The output of 2 to the 30 for a signed int in C on my 32 bit machine
is:
1073741824
The question is how does my computer get 10 digits of precision?
I thought it might be something like
2^K = 10^N
N = K Log (2) //log is base 10
If I let 1 bit for the sign, then K = 31 bits. Plugging 31 into the
above formula yields N roughly equals 9.33.
Now if I let K = 32, N is about 9.63.
In either case, it seems I'm coming out to 9 digits of precision.
Chad
.
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