Re: VOTE on whether 1/oo = 0
From: David W. Cantrell (DWCantrell_at_sigmaxi.org)
Date: 07/14/04
- Previous message: Mark Nudelman: "Re: Can you find anything wrong with this solution to the Halting Problem?"
- In reply to: |-|erc: "Re: VOTE on whether 1/oo = 0"
- Next in thread: |-|erc: "Re: VOTE on whether 1/oo = 0"
- Reply: |-|erc: "Re: VOTE on whether 1/oo = 0"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
Date: 14 Jul 2004 17:53:47 GMT
"|-|erc" <gotch@beauty.com> wrote:
> > Does 1/oo = 0 ?
>
> Thanks to all participants and Kent for his insightful rebuttal on voting
> and maths.
For anyone in sci.logic who may be confused, Herc began his poll in
sci.math two days ago, with the following post:
---------------------------
"|-|erc" <gotch@beauty.com>
wrote:
> Please don't justify your answer or cite reasoning to detract from the
> next voters opinion.
>
> Does 1/oo = 0 ?
>
> oo = infinity
> 0 = zero
> = = equals
> 1 = one
>
> If you're a regular professor here let others vote 1st so as not to
> influence the result.
>
> Just post YES or NO to be counted
>
> Thanks
> Herc
------------------------------------
I'll presume that he thinks it's OK now for "a regular professor here" to
reply. And I feel somewhat compelled to do so since I see that my own words
have been "taken in vain", so to speak.
> No is what I thought that is why I was surprised when Barb Knox claimed
> yes.
>
> With all the other bizzare interpretations of maths I was taught that
> people around here take as correct I had to check.
You thought a poll excluding any "regular professor here" would be a good
way to check! Bah. :-(
I will say, however, that the results of the poll do not really surprise
me, and yet, as explained below, they sadden me somewhat.
Suppose you had taken a poll asking "Does i^2 = -1?", for example. I doubt
that anyone would have responded "No". Why? Because they would naturally
have interpreted the question in a reasonable context, _one in which the
question made sense_! Of course, had someone wished to be difficult, they
could have said "No" and justified their answer easily by saying "In the
real number system, i does not exist and so it is meaningless to speak of
i^2." But that's not a good answer and justification. Nobody in their right
mind would naturally choose to limit themselves to the real number system
when asked "Does i^2 = -1?" Thus, it saddens me that so many respondents to
the poll chose to answer using only a context in which 1/oo is nonsensical,
and then answered "No" accordingly. If asked "Does 1/oo = 0?", the natural
thing to do -- at least for me -- is to choose to answer within a context
in which all parts of the question _make sense_! In _any_ such context
known to me, the answer is "Yes."
Examples of such contexts include the one-point extensions of the real and
complex numbers. An even simpler example is the system [0, oo].
> > >> >Or does 1/oo = 0 now?
> > >>
> > >> It certainly does. For example, have a look at
> > >> <http://mathworld.wolfram.com/AffinelyExtendedRealNumbers.html>,
> > >> item (7). Didn't you already know that?
Yes, that's also an example. But the two-point extension of the reals is
not quite as nice to work with here because 1/0 is undefined in that
extension, and so we cannot say that 0 and oo are reciprocals of each other
there.
> > >"these improper elements are not real numbers, and that this system of
> > >extended real numbers is not a field."
> >
> > Apparently your super-powers do not include reading comprehension.
> > From the same web page:
> > 'The above statements which define results of arithmetic operations on
> > oo may be considered as abbreviations of statements about determinate
> > limit forms. For example, -(+oo) = -oo may be considered as an
> > abbreviation for "If x increases without bound, then -x decreases
> > without bound."'
I was careful in wording that. I said "...may be considered as
abbreviations..." I did not say "...are abbreviations..." or "...must be
considered as abbreviations...", for example. The fact that "The above
statements which define results of arithmetic operations on oo may be
considered as abbreviations of statements about determinate limit forms."
does not mean that it is in any way _best_ to do so. And indeed, at the end
of the paragraph from which that quotation was taken, I mention that some
authors choose to take 0*oo = 0. That _cannot_ be considered to be an
abbreviation of a statement about a determinate limit form since the
corresponding limit form is indeterminate.
> Which means 1/oo = 0 is an abbreviation for lim(x->oo) 1/x = 0
As I had said, you _may_ think of it that way. But I prefer to think of
lim(x->oo) 1/x = 0 as being the reason why we clearly want to have 1/oo = 0
in an extended system such as [0, oo]. Within such a system, once its
elements and operations have been defined, 1/oo = 0 _per se_. That equation
need not be regarded as being merely an abbreviation.
The only time that 1/oo = 0 _must_ be regarded as being merely an
abbreviation is when we are dealing with systems such as the (unextended)
real or complex numbers. They lack an infinite element, and so 1/oo, taken
literally, is nonsensical in them.
> That first "=" is not equals.
Within an extended number system, it does represent equality.
> You are better off using notation 1/oo <=> 0
I wouldn't say so. That notation would probably be confusing. Better to
work within an extension where "=" means "equals".
> I do have a liberal perspective on the topic also.
>
> IF you define division by infinity to start with
> THEN you could assign that result as 0.
I advise against doing that.
It's better to define the elements of the extension and the appropriate
operations _in general_ first. Done correctly, 1/oo = 0 would then follow
as naturally as, say, 6/2 = 3. There would be no need to consider "division
by infinity" as being a special case.
> But like someone pointed out a/b = c <-> a/c = b which doesn't work
> with division by 0.
Certainly 0/5 = 0 doesn't imply that 0/0 = 5, for example. But more
pertinently for this thread, note that (1/b = c iff 1/c = b) _does_ work
perfectly well in the one-point extensions of the real and complex numbers,
and in the system [0, oo]. That's one reason why, in such systems, it's
reasonable to call 0 and oo _reciprocals_ of each other, despite the fact
that they are not multiplicative inverses.
Maybe you didn't correctly state what "someone pointed out". Perhaps they
had instead said something like (a/b = c implies a = b*c). That implication
is true in the real and complex number systems, but false in their
extensions, in which division is not defined directly in terms of
multiplicative inversion.
David W. Cantrell
- Previous message: Mark Nudelman: "Re: Can you find anything wrong with this solution to the Halting Problem?"
- In reply to: |-|erc: "Re: VOTE on whether 1/oo = 0"
- Next in thread: |-|erc: "Re: VOTE on whether 1/oo = 0"
- Reply: |-|erc: "Re: VOTE on whether 1/oo = 0"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]