Re: VOTE on whether 1/oo = 0
From: George W. Cherry (GWCherryHatesGreenEggsAndSpam_at_alum.mit.edu)
Date: 07/15/04
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Date: Thu, 15 Jul 2004 03:02:19 GMT
"|-|erc" <gotch@beauty.com> wrote in message
news:S1mJc.1635$K53.709@news-server.bigpond.net.au...
> "David W. Cantrell" <DWCantrell@sigmaxi.org> wrote in
> > "|-|erc" <gotch@beauty.com> wrote:
> > > "David W. Cantrell" <DWCantrell@sigmaxi.org> wrote
> > > > "|-|erc" <gotch@beauty.com> wrote:
> > > > > "David W. Cantrell" <DWCantrell@sigmaxi.org> wrote in
> > > > > > > I do have a liberal perspective on the topic also.
> > > > > > >
> > > > > > > IF you define division by infinity to start with
> > > > > > > THEN you could assign that result as 0.
> > > > > >
> > > > > > I advise against doing that.
> > > > > > It's better to define the elements of the extension and the
> > > > > > appropriate operations _in general_ first. Done correctly, 1/oo
= 0
> > > > > > would then follow
> > > > >
> > > > > notice my disclaimer before I state that the result could be 0.
> > > > >
> > > > > If you were given a test
> > > > >
> > > > > 1/oo =
1/oo = 0.125
8 is 8 at any angle, even repose.
However, limit 1/N is 0 as N grows without bound.
However, note:
Theorem: The limit of sin x/n as n grows without bound is 6.
Proof: cancel the n in the numerator and denominator.
George W. Cherry
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