Re: Zenkin's paper on Cantor
From: Eray Ozkural exa (erayo_at_bilkent.edu.tr)
Date: 10/07/04
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Date: 7 Oct 2004 01:51:36 -0700
daryl@atc-nycorp.com (Daryl McCullough) wrote in message news:<ck26jh030rb@drn.newsguy.com>...
> Eray Ozkural exa says...
> >
> >Ralph Hartley <hartley@aic.nrl.navy.mil> wrote
>
> >> If you give me a list of real numbers, presented in that way, I can give
> >> you a number not on your list.
> >
> >A timely observation which takes us to the heart of the matter. I will
> >argue that I cannot "give you a list".
>
> You can give me a *procedure* which, given a number n
> returns the nth real number (between 0 and 1, for simplicity),
> which in turn is a procedure which, given a number m, returns
> the mth bit of the binary expansion of that real.
Yes, of course, Daryl, that is quite obvious. I can for instance use a
regular subdivision procedure which, given a number n, returns the
number "0.binary(n)".
I can also guarantee that the nth number has at least n digits after
the (binary) point (I think this is easily done). But the above method
doesn't hold then, you have to use something like "0.<n 0's>1".
Now, giving the list in this fashion would be potential infinity,
since it is compressed in a finite nonhalting program. My post is in
error, the second proof also can be said to be valid from a
constructivist perspective, if the reals chosen are deliberately taken
to be computable in exactly this way.
I think this way, the essence of the proof is actually demonstrated
better; note the similarity of my representation above to the fact
that the measure of the countable reals in (0,1) is 0. (but of course
different representations are possible)
I am pleased with this interpretation of the proof. The later steps of
the proof can be merged in a nonhalting procedure which uses the
generator above, the reasoning part is still infinitary, but I think
it is inductively true (I can try to explain this part if it doesn't
make sense to you). Now, everything is explained bottom-up, when we
are dealing only with a *computable* list of computable reals. (The
actual infinity remains in the continuum, the proof has nothing to do
with it.)
But I do not think that Cantor's original proof is in fact
constructive in the sense of *constructivism*. (I'm aware that a
realist might call it constructive!)
Regards,
-- Eray Ozkural
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