Infinite number of infinite coin flips
From: Bill Smythe (chichess_at_beforeRCNafter.com)
Date: 01/19/05
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Date: Wed, 19 Jan 2005 10:46:48 -0600
"Ed Murphy" wrote:
> To summarize:
>
> P = number of people
> C = number of coin flips per person
>
> If P is countably infinite and C is countably infinite, then the
> diagonal argument works.
>
> If P is countably infinite and C is uncountably infinite, then the
> diagonal argument still works. (Consider a countably infinite
> subset of each person's sequence of coin flips. This case now
> reduces to the previous case.)
>
> If P is uncountably infinite, then the diagonal argument doesn't
> work. (It relies on a bijection from the set of people to the
> natural numbers; if P is uncountably infinite, then by definition
> there isn't one.)
What if P and C are both uncountably infinite (say, to the same degree of
aleph-whatever)? Is there a variation of the diagonal argument which will
work in this case?
> And now let's set aside all these side issues that may or may not
> pertain, and revisit your original question. "How many digits is
> pi computable to?" ....
You're right, we should have changed the thread title a long time ago -- as
I have now done.
> .... Or, to avoid digressions into practical physics,
> and also to explicitly address the difference between countable and
> uncountable infinities: "Does the complete decimal expansion of pi
> consist of a countably or uncountably infinite number of digits?"
Huh?? The first digit after the decimal point is number 1. The next is
number 2. Etc. There's your bijection.
Bill Smythe
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