Re: Not constructive proof of existing of an algorithm

From: "Yajun" <yalding@xxxxxxxxx>
Date: 22 Apr 2005 04:33:42 -0700

I somehow get the idea. Then we fall into another assumption that
sounds intuitive:

For fixed $d$, the set of "problematic subgraphs" can be computed in
finite steps only depend on $d$.

But I am curious about this assumption.

regards,
yalding

.

Follow-Ups:
- Re: Not constructive proof of existing of an algorithm
  - From: tchow

References:
- Not constructive proof of existing of an algorithm
  - From: Iron Bone
- Re: Not constructive proof of existing of an algorithm
  - From: Mike Robson
- Re: Not constructive proof of existing of an algorithm
  - From: googmeister
- Re: Not constructive proof of existing of an algorithm
  - From: Yajun
- Re: Not constructive proof of existing of an algorithm
  - From: Christian Kleinewaechter

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