Re: Can any one have solution???
- From: Aaron Lint <alint@xxxxxxxxxxxxx>
- Date: Tue, 23 Aug 2005 23:39:39 -0500
Kumar wrote:
ya
More specifically, If the alphabet is {a} L = a^k | k is prime
for clarity: a^k = aaaaaa...aaaa (k a's)
-Aaron .
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