Re: More beginner questions about SAT...
- From: sasha mal <sashaREMOVEIT.mal@xxxxxxxxxxxxxxxxx>
- Date: Thu, 21 Sep 2006 22:31:23 +0200
Russell Easterly wrote:
"sasha mal" <sashaREMOVEIT.mal@xxxxxxxxxxxxxxxxx> wrote in messageExactly when
news:eervm0$df4be$2@xxxxxxxxxxxxxxxxxxxxxxxxxxx
My question would be:
is there a SAT solving algorithm working in poly(number of variables n)
and exp(number of clauses m), smth. like O(n^9 * 2^m)?
For 3SAT there are 3^m possible ways to choose one
element from each clause. This isn't much of an algorithm since
usually 2^n < 3^m.
m > n (log 2) / (log 3), i.e.
m > n 0.6309...
So what?
Sasha.
.
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- More beginner questions about SAT...
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- Re: More beginner questions about SAT...
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- Re: More beginner questions about SAT...
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- More beginner questions about SAT...
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