Re: An algorithm with Minimum vertex cover without considering its performance



Patricia Shanahan wrote:
L is a vertex cover, but not necessarily minimal.

Consider the single edge, two vertex, graph V={1,2}, E={{1,2}},
adjacency matrix:

0 1
1 0

L would be {1,2}, but {1} is also a vertex cover, as is {2}.

Perhaps I'm not understanding what a vertex cover is. I thought a
vertex cover was just the set of all vertices which are incident to
edges in E. I guess I'll have to research what a vertex cover is in
more detail.

Sorry...

.



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