Re: proving string has atmost k length whose NFA has k states
- From: "Rupesh Bhochhibhoya" <bhochhi@xxxxxxxxx>
- Date: 15 Oct 2006 00:16:24 -0700
Rick Decker wrote:
Rupesh Bhochhibhoya wrote:
Hi everybody,It would have been helpful to state the question. I have a copy of
I'm new member of this group. My question is actually from the book by
Micheal Sisper chapter 1 ex:1.64. I can show that there is always a
string with atmost k-1 length for the NFA with k states but not able to
show string has atmost k states. Either I'm getting the question
incorrectly or my knowledge is insufficient or whatever. But I'm not
expecting for whole answer. I would be glad if i get some hints.
Thanks in advance..
Rupesh
Sipser, but not everyone does (though perhaps they should--it's a
very good book, IMO). The problem states:
Let N be an NFA with k states that recognizes some language A.
(a) Show that, if A is nonempty, A contains some string of length
at most k.
The "at most k" part doesn't require that there _is_ a string
in A of length k; it just requires a that there is some string
in A of length <= k. As you correctly note, in this problem
"at most k" can be replaced with "less than k."
Actually, now that I think of it, I suspect that it should be
"less than k" for later use in part (b).
Regards,
Rick
Rick,
Thank you for the hint. Now I got how to proceed further. Thanks to
this group....
Sincerely, Rupesh
.
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- proving string has atmost k length whose NFA has k states
- From: Rupesh Bhochhibhoya
- Re: proving string has atmost k length whose NFA has k states
- From: Rick Decker
- proving string has atmost k length whose NFA has k states
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