Re: Discussion about transformation TSP to UniqueTSP
- From: Bryan Olson <fakeaddress@xxxxxxxxxxx>
- Date: Thu, 30 Nov 2006 07:28:24 GMT
mathisart wrote:
Bryan Olson wrote:deepakc wrote:Bryan Olson wrote:A counter-example along different lines: Language Q1 is the
set of strings that begin with a '1', followed by a Turing
Machine that halts on empty input. Language Q2 is the set of
strings that are either
a '1' not followed by a TM that halts on empty input,
or
a '0' followed by a graph with a Hamiltonian cycle.
I'm assuming reasonable encodings are a given. The union of
Q1 and Q1 is NP-Complete. Q1 and Q2 are both non-empty, and
neither is NP-Complete because neither is even in NP.
This is clever! But I think it is not possible, even in a broad sense.
"reasonable encodings" is one monsterous assumption!
Good theory texts will go into some detail, showing how to
build the needed encodings. It's tedious, and encoding
issues are not particularly interesting. The complexity
classes at issue are sets of languages, so all the problems
we're discussing assume some encoding of problem instances
into strings.
Tim Chow offered the same counter-example in <456da3e4$0$24622$b45e6eb0@xxxxxxxxxxxxxxxxxxxxxxxxx>. Maybe
you'll like his wording better.
You are obviously
a formalist. ;-p
Not really. As long as everyone understands the formalism,
there's no problem with talking informally. Things go awry
when people start trying to reason about these things without
understanding what the informal terms actually stand for.
A second, slightly stronger objection to that same given, is that Q2 is
the union of all languages,
It really isn't.
even Q1 (reduce, toss the first bit, and
for that matter, the TM, convert the whole thing to its "contained
string").
Why are you tossing and converting things like that?
[...]
Why is it that if there is a single NP problem that is not NPC, then
P=NP? I know I've read the statement but not the reasoning.
If you understood the reasoning, you'd see that you have things
kind of backwards.
--
--Bryan
.
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