Re: Graph Coloring
- From: tchow@xxxxxxxxxxxxx
- Date: 20 Jan 2007 17:15:41 GMT
In article <1169252592.272319.296370@xxxxxxxxxxxxxxxxxxxxxxxxxxx>,
Proginoskes <CCHeckman@xxxxxxxxx> wrote:
Abid wrote:
1--If there are more than one pairs of nodes that donot have edges
between them , then atleast one pair will have same color.
I don't think so. The pentagon has chromatic number 3 (it requires 3
colors), and any 3-coloring (up to symmetry) looks like 12123 (going
around the cycle). If v1 and v3 are colored 1, v2 and v4 colored 2, and
v5 colored 3, then you have the two pairs (v5,v1), (v3,v2) show the
claim is false.
No, this doesn't work, because v1 and v3 have the same color.
Abid's claim can be restated as: if a *minimum* coloring of a graph is
a *legal* coloring of its complement, then the graph is complete.
I don't immediately see a proof or a counterexample.
--
Tim Chow tchow-at-alum-dot-mit-dot-edu
The range of our projectiles---even ... the artillery---however great, will
never exceed four of those miles of which as many thousand separate us from
the center of the earth. ---Galileo, Dialogues Concerning Two New Sciences
.
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