PSPACE closed under union



Hi,

I have trouble proving PSPACE is closed under union, complementation
and star.

But for now, I want to know how to prove for under UNION only.

I know that we have to:
Let L1 in PSPACE and L2 in PSPACE.
Want to show: L1 U L2 in PSPACE

How to show that?

.



Relevant Pages

  • Re: Problems in NP^(NP^NP) that are not in NP^NP?
    ... why can't we say that PH = PSPACE? ... This is a common confusion. ... Since PH is the union of its levels, any problem in PH must belong to ... Dialogues Concerning Two New Sciences ...
    (comp.theory)
  • Re: Problems in NP^(NP^NP) that are not in NP^NP?
    ... why can't we say that PH = PSPACE? ... This is a common confusion. ... Since PH is the union of its levels, any problem in PH must belong to ... Thanks for clarifying. ...
    (comp.theory)