Re: Most Natural Numbers Are Uncomputable
- From: Owen Jacobson <angrybaldguy@xxxxxxxxx>
- Date: Mon, 27 Jul 2009 02:16:49 -0400
On 2009-07-26 23:06:47 -0400, Tim Little <tim@xxxxxxxxxxxxxxxxxx> said:
On 2009-07-26, RussellE <reasterly@xxxxxxxxx> wrote:
and therefore BNTM will "eventually" write every finite string of
1's.
It does write every finite string of 1's. It just does not write an
infinite string of 1's.
It's probably worth pointing out[0] that there is no natural number n where, at the n'th step, the BNTM has written all finite strings of 1s. It's only in the limit, after more than finitely many steps, that it "has written" more than finitely many finite strings of 1s, and can therefore "have written" N.
The quotes are there because the behaviour after infinite number of iterations cannot be used to draw random conclusions about the behaviour after finite numbers of iterations.
One of the benefits of describing systems like Turing machines in terms of functions on sets is that you can do away with the sort of verbal ambiguity that comes from ad-hoc descriptions. In particular, it's very easy to demonstrate that, for a system containing
f_0 = ""
f_n = f_(n - 1) + "1"
|f_n| = n [read |x| as 'length of x' here -oj]
that, if n is a natural number, then no f_n contains infinitely many 1s, and that every natural number of 1s has a corresponding f_n. We can, with effort, formally prove that
Ax Ey |f_y| > x
is true, and that
Ey Ax |f_y| > x
is false for x and y as natural numbers. In fact, we can strip this down even further:
Ax Ey y > x
is true, and
Ey Ax y > x
is false so long as x and y are natural numbers. Similarly, if we admit values of n in f_n that are not natural numbers, then we can prove different, interesting things, including that
Ax |f_omega| > x
where x is a natural number.
When you get to even this minimal level of formalism, RusselE's "contradiction" evaporates like a bad dream: by moving from *apparent* precision, framed in words like "eventually" and "writes" to *formal* precision, framed in terms of structured sequences of symbols, Russel's non-sequiter "contradiction" is shown for the broken argument it is.
Words are *not* enough.
-o
[0] To Russel and those like him, *again*, because it surely hasn't stuck yet...
.
- Prev by Date: Re: So much for this group!
- Next by Date: Re: Most Natural Numbers Are Uncomputable
- Previous by thread: Naz - Computers and Laptops
- Next by thread: Re: Most Natural Numbers Are Uncomputable
- Index(es):
Relevant Pages
|