Re: newbie question about java's syntax


"donovan" wrote...
>I have a background in c++ and this syntax looks basically
> just like C++. What throws me off is the first line and
> the last line. I'm thinking it's a statement because it
> has ; at the very end,

It is. If you look more closely, you'll see that it ends the following
statement:

ipField.addFocusListener( ... );


> but it looks like a function definition sqeezed in
> as an argument of a function call.

Not quite, but almost... ;-)

You're instantiating an object, which will be the argument of the function
call:

ipField.addFocusListener(new FocusAdapter() {...} );

> Can someone give me a clue?

As FocusAdapter is an abstract class, you need to implement an own subclass
of it, which in Java can be done "anonymously", i.e. without giving it a new
class name, just as you've done.

new FocusAdapter() {
public void focusLost(FocusEvent e) {
ipField.selectAll();
if (connectionStatus != DISCONNECTED) {
changeStatusNTS(NULL, true);
}
else {
hostIP = ipField.getText();
}
}
}

// Bjorn A


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