Re: Multiple bounds in a generic declaration

Gibbering wrote:
If I need an arraylist of objects who extend something and implement
something else, how can I declare it?

ArrayList<? extends Foo & Bar> funky = new ... // Invalid
ArrayList<? extends Foo, Bar> funky = new .... // Invalid

Both Foo is an abstract class and Bar is in this case a listener
interface. How can I declare this ArrayList?


More confusion over type bounds. This kind of bound is only used for generic methods, parameters and class definitions, not actually declaring a variable or object. (I think I've used "define" and "declare" correctly there.)

abstract class Foo implements Bar, ActionListener {}

ArrayList<Foo> funky;

is probably what you want. Don't use a bound or wildcard when declaring a variable like "funky".


.

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