Re: Export all classes in call graph?

Robert Mischke wrote: 
With "call graph" I mean the set of all classes that may be directly
or indirectly used from classes you specify.

A call graph works on method-level, not class level (often, for the purpose of a call graph, constructors are also treated as methods). A call graph indicates which methods (of which classes) are used (are "called") by other methods, not just which classes somewhat dependent on each other.

You are probably after compile-time dependency or class dependency, not a call graph.

In the example below, B and C are in the call graph of A, while D is
not.


"in the call graph of A" has no meaning. You probably mean "children of A".

> In Java, the call graph can be easily found by following the 
"import" statements, as long as they are accurate and don't use "*"s
(because this also includes classs that are not neccesarily in the
call graph).

This is absolutely wrong. Import statements introduce a compile-time dependency, but not necessarily a class dependency. And, if no method is used from the imported class, the imported class would also have no business in showing up in a call-graph.

	import A;

	/** never uses A **/
	class B {
		int ten() { return 10; }
	}

You can only compile this, when A is in the CLASSPATH (compile-time dependency), but you can change A as much as you like without having an influence on B (no class dependency). And since B uses nothing of A, no method of A would ever appear as a children of a method of B in a call-graph.

/Thomas

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