Re: java.lang.OutOfMemoryError: Java heap space

Don't know, how much is that an SSCCE, but I am posting you my example:

import java.util.ArrayList;
import java.util.BitSet;
import java.util.Collection;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

public class Example {

private class ArrElem {

private String id;
private BitSet fp;

public BitSet getFp() { return fp; }
public void setFp(BitSet fp) { this.fp = fp; }
public String getId() { return id; }
public void setId(String id) { this.id = id;}
}

private List<ArrElem> arr = new ArrayList<ArrElem>();

private Map<ArrElem, Collection<ArrElem>> rez = new HashMap<ArrElem,
Collection<ArrElem>>();

public void processArr() {
//fillArr(10000);
for (int i = 0; i < 10000-1; i++) {
for (int j = i+1; j < 10000; j++) {
compareElements(arr.get(i), arr.get(j));
}
}
}

private void compareElements(ArrElem elem1, ArrElem elem2) {
int bitM = elem1.getFp().cardinality();
int bitN = elem2.getFp().cardinality();

BitSet commonBits = elem1.getFp();
commonBits.and(elem2.getFp());
int bitCommon = commonBits.cardinality();

double index = bitCommon/(bitM+bitN+bitCommon);
if (index < 0.8) {
if (! rez.containsKey(elem1))
rez.put(elem1, new ArrayList<ArrElem>());
rez.get(elem1).add(elem2);
}
}
}


Daniel Pitts wrote:
Goofball wrote:
Does anyone have any ideas on why that happened:

[java] Exception in thread "main" java.lang.OutOfMemoryError: Java heap
space

Explaining the situation. I have such code:

for (int i=0; i<10000-1; i++) {
for (int j=i+1; j<10000; j++) {
compareElements(arr[i], arr[j]);
}
}

Element of the array is a simple class that has two fields (one is
string and another is BitVector) and getters and setters for those
fields. Function compareElements compares the BitVectors of two
elements.

Now the problem: when I run the code, program runs only till then 1334
element in the first cycle. Then I receive the above exception.

Does anyone know, what can that be? Thanks for any help.

If you post an SSCCE (http://www.physci.org/codes/sscce/), we would be
better able to help you.

.

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