Re: Tricky regex question

On Jan 31, 11:08 am, "Oliver Wong" <o...@xxxxxxxxxxxxxx> wrote:
"Juan Singh" <j...@xxxxxxxxxxxxx> wrote in message

news:6aednfAhprlueF3YnZ2dnUVZ_uHinZ2d@xxxxxxxxxxxxxx



Hi,

I need to split words from a sentence that are more than 2 letters. An
example sentence is:

This is "very" 'tricky'. I won't be able see it.

I came up with the following regex, but it breaks the word [won't] and I
only get the part that is before the single quote.

\b[a-zA-Z]{2,}+\b

My objective is to extract the following words from the example sentence
above.

This, very, tricky, won't, able

I'd split the string on whitespace (to get {This, is, "very", 'tricky'.,
I, won't, be, able, see, it.}) and then write a function which acts like
trim(), but rather than removing leading or trailing whitespace, it removes
leading or trailing punctuation. That'll give {This, is, very, tricky, I,
won't, be, able, see, it} which you can then walk through and eliminate all
2 char characters or less.

- Oliver
I was going to suggest this, then I realize that there IS a regex that
can do it.
\w+('?\w){2,}
I even posted an SSCCE to show how it works.

.