Tomcat write directory of received files????
From: jajoo (jivkoto_at_abv.bg)
Date: 01/27/04
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Date: 27 Jan 2004 04:11:09 -0800
Hi everyone,
I am trying to send files with multipart/form-date. Everything is ok
with the send.
But when I am receiving the files I should specify a directory where
the files to be saved. The problem is that Tomcat saves the files into
%CATALINA_HOME%/bin directory. I am wondering why? Why not into my
application directory?
The application directory is %CATALINA_HOME%/webapps/picture.
As a parameter of directory I am giving "." – which means – the same
directory.
Is there another solution except giving directory
"../webapps/pictures"
Here is the jsp code that sends the files.
<%@ page contentType="text/html; charset=windows-1251" errorPage="" %>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html;
charset=windows-1251">
<title>Send Multiple</title>
<body>
<h1>Page for sending files:</h1>
<form name="send" action="receive.jsp" method="post"
enctype="multipart/form-data">
<input type="text" name="text" value="Tova e text">
<p>
<input name="file1" type="file" id="file1">
</p>
<p> <input type="file" name="file2">
</p>
<p>
<input type="submit" name="Submit" value="Submit">
</p>
</form>
</body>
</html>
Here is the jsp code that receives the files:
<%@ page contentType="text/html; charset=windows-1251" errorPage=""
%>
<%@ page import="java.io.*"%>
<%@ page import="java.util.*"%>
<%--@ page import="com.oreilly.servlet.*"--%>
<%--@ page import="com.oreilly.servlet.multipart.*"--%>
<%@ page import="com.oreilly.servlet.MultipartRequest"%>
<%@ page import="org.apache.commons.fileupload.*"%>
<%@ page import="com.oreilly.servlet.multipart.DefaultFileRenamePolicy"
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html;
charset=windows-1251">
<title>Receive</title>
</head>
<body>
<h1>Receive page:</h1>
<%
String dir = request.getContextPath();
MultipartRequest multi = new MultipartRequest(request,".");
// the problem is what to specify here insetead ".", or what to do
with
// TOMCAT to save in my application directory??????
Enumeration fnames = multi.getFileNames();
while(fnames.hasMoreElements()){
String name = (String)fnames.nextElement();
out.println(name);
}
boolean isMultipart = FileUpload.isMultipartContent(request);
/* - another package for multipart/form-date … using
../webapps/picture/images
DiskFileUpload upload = new DiskFileUpload();
List items = upload.parseRequest(request);
Iterator itr = items.iterator();
while(itr.hasNext()) {
FileItem item = (FileItem) itr.next();
// check if the current item is a form field or an uploaded
file
if(item.isFormField()) {
// get the name of the field
String fieldName = item.getFieldName();
out.println(fieldName+" "+item.getString());
// if it is name, we can set it in request to thank the user
if(fieldName.equals("name"))
request.setAttribute("msg", "Thank You: " +
item.getString());
} else {
// fullFile.getName().
out.println(item.getFieldName()+" "+item.getName());
try{
String filename = item.getName();
//out.println(filename);
//Check if the file exist
if(filename!=null&&item.getSize()>0){
File fullFile = new File(item.getName());
//File savedFile = new
File(getServletContext().getRealPath("/"),fullFile.getName());
File savedFile = new
File("../webapps/picture/images",fullFile.getName());
item.write(savedFile);
}
else out.println("No such file:
"+item.getName());//File not specified
}catch(Exception e){out.println("Exception: "+e);}
}
}
*/
%>
</body>
</html>
If anybody could help I would be THANKFUL.
- Next message: Mark A. Washburn: "Re: Programming languages for the very young"
- Previous message: Dave Rathnow: "Anyone using J2ME in non-commercial applications?"
- Next in thread: Ryan Stewart: "Re: Tomcat write directory of received files????"
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