Re: programmatically determine if argument is list compatible to a given lambda list
- From: Pascal Bourguignon <pjb@xxxxxxxxxxxxxxxxx>
- Date: Sun, 29 Apr 2007 23:32:37 +0200
Pascal Costanza <pc@xxxxxxxxx> writes:
Pascal Bourguignon wrote:
jimka <jimka@xxxxxxxxx> writes:
I'd like to write a function which at run-time will determine whether
a given list
of arguments is compatible to a given lambda list.
For example.
(callable-as '(3) '(x))
==> return t because you CAN apply (lambda (x) nil) to '(3)
(callable-as '(3) '(x &rest y))
==> return t because you CAN apply (lambda (x &rest y) nil) to '(3)
(callable-as '(3) '(x y))
==> return nil because you CANNOT apply (lambda (x y) nil) to '(3)
Here is my attempt which fails miserably.
(defun callable-as (arg-list lambda-list)
(unwind-protect (apply `(lambda ,lambda-list
(return-from callable-as t))
arg-list)
(return-from callable-as nil)))
This is dangerous.
What if the lambda list is:
(x &optional (y (delete-file "/some/important/file")))
to not write anything worse ?
You can call any function with (delete-file "/bla") as one of its
parameters. ?!?
The point is that you can put side effects in the lambda-list:
C/USER[32]> (defvar *x* 0)
*X*
C/USER[33]> (defun f (x &optional (y (incf *x*))) (values x y))
F
C/USER[34]> (f 1)
1 ;
1
C/USER[35]> (f 1)
1 ;
2
C/USER[36]> (f 1)
1 ;
3
C/USER[37]> *x*
3
C/USER[38]>
--
__Pascal Bourguignon__ http://www.informatimago.com/
"Klingon function calls do not have "parameters" -- they have
"arguments" and they ALWAYS WIN THEM."
.
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- programmatically determine if argument is list compatible to a given lambda list
- From: jimka
- Re: programmatically determine if argument is list compatible to a given lambda list
- From: Pascal Bourguignon
- Re: programmatically determine if argument is list compatible to a given lambda list
- From: Pascal Costanza
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