Re: Ruby in Lisp

alflisppython@xxxxxxxx writes:

I would like to know if there is any implementation of Ruby in Lisp.

I think that the idea of using the dot for eliminating parenthesis
is a very
good one:

I prefer l.length to (length l)

Do any of you have an automatic way of doing something like this,
that is

First: Detect that a function has only 1 argument, then transform

(f a) into a.f

Second: Detec that f has more than one argument, transform

(f a b) into a.f(b) etc.

Third. Use multiple times this idea:

(first (last l)) -> l.last.first

Please, i like to have this small programm to play with it.

Thanks to all the people in this lisp channel for a possible answer.

You'd have to write a parser for your syntax and generate a sexp to be
evaluated for each expression. You can implement this in an afternoon.


--
__Pascal Bourguignon__ http://www.informatimago.com/

NOTE: The most fundamental particles in this product are held
together by a "gluing" force about which little is currently known
and whose adhesive power can therefore not be permanently
guaranteed.
.

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