unique situation, fopen, mysql can't be called

From: Jonah (nomail_at_nomail.com)
Date: 04/28/04 

Date: Wed, 28 Apr 2004 12:08:04 -0400

Hi

I've run some tests and I have to conclude that
mysql and fopen doesn't work when you call it in this way.

I don't understand why, it's got to be either one of 2 things:
a) this just can't be done, and I'm ignorant of why
b) there is a workaround and/or i'm doing this the wrong way

Hopefully someone can enlighten me?

Here's the situation:

HTML PAGE
img src=script1.php

SCRIPT1.PHP
//redirects to script2.php
header(Location: $urltoscript2)

SCRIPT2.PHP
//writing to a file doesn't work
//writing to a table in mysql doesn't work
header(Location: $urltoimage)

Information can be passed via query string from the
html page to script1, to script 2, and the image
does get displayed, but mysql and writing
to a file just won't work unless you call script2 directly.

I have tested this in the following way:

1) I tried accessing the html page which displays img src,
script2.php didn't write to mysql as intended

2) I tried accessing script1.php directly,
script2.php didn't write to mysql as intended

3) I tried accessing script2.php directly,
script2.php DID write to mysql successfully

Same goes for writing to a file.

How can I make this work?
Any ideas?

Thanks for your time.

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