Re: Need expert assistance with this (MySQL routine)



giancarlodirisioster@xxxxxxxxx wrote:

Hmm, now after changing that now I get parse error, unexpected '}' in
/usr/home/test.php on line 15

Weird. Do you have this right now? :

$query = "SELECT table.column1 FROM table";
$result = mysql_query($query);
while($column = mysql_fetch_array($result))
{
	$column1 = $column['column1'];
	$update = "UPDATE test SET column2 = ''
		WHERE column2 = '$column1'";
	mysql_query($update);
}

Definitely, I have a customer and customer1 table (I know, for
consistency I should have customer1 and customer2), but I definitely
have two separate tables

I did a little test for you with a customer table and a customer1 table, looking like this:


customer:
id	name
=============
1	john

customer1:
id	name
=============
1	pete
2	john
3	ruben

I used the following query:
DELETE customer1 from customer1,customer WHERE customer1.name=customer.name;

This deletes the row with id=2 and name=john from the table customer1.

--
http://www.phpforums.nl
.