Re: Need expert assistance with this (MySQL routine)
- From: Peter van Schie <vanschie.peter@xxxxxxxxx>
- Date: Sun, 30 Oct 2005 01:59:51 +0200
giancarlodirisioster@xxxxxxxxx wrote:
Hmm, now after changing that now I get parse error, unexpected '}' in /usr/home/test.php on line 15
Weird. Do you have this right now? :
$query = "SELECT table.column1 FROM table";
$result = mysql_query($query);
while($column = mysql_fetch_array($result))
{
$column1 = $column['column1'];
$update = "UPDATE test SET column2 = ''
WHERE column2 = '$column1'";
mysql_query($update);
}Definitely, I have a customer and customer1 table (I know, for consistency I should have customer1 and customer2), but I definitely have two separate tables
I did a little test for you with a customer table and a customer1 table, looking like this:
customer: id name ============= 1 john
customer1: id name ============= 1 pete 2 john 3 ruben
I used the following query: DELETE customer1 from customer1,customer WHERE customer1.name=customer.name;
This deletes the row with id=2 and name=john from the table customer1.
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