Class ErrorException and inheritance

Hello all,

maybe one of you can give me an answer to the following question:

Since PHP 5.3, the class \ErrorException (which extends \Exception) has
the constructor

ErrorException::__construct
(
[ string $message
[, long $code
[, long $severity
[, string $filename
[, long $lineno
[, Exception $previous = NULL
]]]]]]
)

By default, the object $e coming up with

[1] try
[2] {
[3] throw new ErrorException($message, $code, $severity);
[4] }
[5] catch (ErrorException $e)
[6] {
[7] }

has methods $e->getFile() and $e->getLine() which return the filename
resp. the line number where the exception was thrown.

Assume, you define a new class

SuperErrorException extends ErrorException,

the constructor of the subclass should at least contain the same
parameters, e.g.

namespace Super;
class SuperErrorException extends \ErrorException
{
public function __construct
(
$message = '',
$code = 0,
$severity = 0,
$filename = NULL, (A)
$lineno = NULL, (B)
Exception $previous = NULL
)
{
parent::__construct
(
$message,
$code,
$severity,
$filename,
$lineno
);
}
}

Here, $filename and $lineno are NULL by default to make the parameters
optional (as in ErrorException).

The problem:

[1] try
[2] {
[3] throw new SuperErrorException($message, $code, $severity);
[4] }
[5] catch (ErrorException $e)
[6] {
[7] }

will call SuperErrorException::__construct which overwrites the defaults
for $filename and $lineno with NULL.

Replacing $filename and $lineno in (A) and (B) by __FILE__ and __LINE__
is not the solution!

What can be done to give SuperErrorException the same core functionality
as ErrorException?

Kind regards,
Werner
.

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