Re: default function argument issue

From: Alvaro G Vicario (alvaro_QUITAR_REMOVE_at_telecomputeronline.com)
Date: 03/23/04 

Date: Tue, 23 Mar 2004 17:36:52 +0100

*** Brad Kent wrote/escribió (23 Mar 2004 08:16:53 -0800):
> array() is a constant

Actually, it's a language construct. A constant would be something like
M_PI. But you are right, your code works.

I hadn't tested your original code. I've done it now and it works fine for
me, just correcting a typo —you define test() and call foo()—:

This:

        function test($foo=array()) {
                echo gettype($foo);
                implode(' ',$foo);
        }

        test();

prints:

        array 

-- 
-- 
-- Álvaro G. Vicario - Burgos, Spain
--

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