Re: MySQL link, PLEASE help!?!?
From: Will Clifton (wgcabp_at_cox.net)
Date: 11/23/04
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Date: Tue, 23 Nov 2004 09:02:58 -0600
On Tue, 23 Nov 2004 09:40:17 -0500, Sundial Services wrote:
> It seems to me that your code should:
>
> $result = mysql_query("SELECT image FROM table WHERE id=$id")
> ...
THANK YOU for reading, however that's precisely what I've been trying to
do. I even had that exact same code at one point and it returns a MySQL
syntax error where I put the variable in the query. Sigh. Still lost, any
other ideas?
Will
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