Re: array structure as with array_reverse preserve_keys

Bosconian wrote:
I have an array defined as follows:

$scores[2] = 19;
$scores[4] = 25;
$scores[2] = 23;
$scores[4] = 25;

... where the key is the team # and the value is the points.

I am outputting the key/values as follows:

foreach ($scores as $team => $points) {
echo "Team: $team, Points: $points, Difference: " . ($scores[0] -
$scores[1]) . "<br>";
$scores = array_reverse($scores, false);
}

Curent output (before array_reverse):

Game 1
Team: 2, Points: 19, Difference: 0
Team: 4, Points: 25, Difference: 6

Game 2
Team: 2, Points: 23, Difference: 0
Team: 4, Points: 25, Difference: 2


A problem occurs when calculating the point "Difference". The first pass of
the foreach loop (above) is incorrect, but the second pass is correct
(below.) This is due from the use of the function array_reverse(). By
setting the preserve_keys to false, the function changes the structure of
the array.

Desired output (after array_reverse):

Game 1
Team: 2, Points: 19, Difference: -6
Team: 4, Points: 25, Difference: 6

Game 2
Team: 2, Points: 23, Difference: -2
Team: 4, Points: 25, Difference: 2


Question: how can the above array be structured like this from the start?



Well, first of all:

$scores[2] = 19;
$scores[4] = 25;
$scores[2] = 23;
$scores[4] = 25;

doesn't work. You have scores[2] contain both 19 and 23, which you can't do.

Secondly, the line:

echo "Team: $team, Points: $points, Difference: " . ($scores[0] -
$scores[1]) . "<br>";

Would always print the difference between $scores[0] and $scores[1] - that is, -6.

So - what's your real code look like?


--
==================
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Jerry Stuckle
JDS Computer Training Corp.
jstucklex@xxxxxxxxxxxxx
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