Re: visibility matter on converting object to array

"gg9h0st" <mn9h0st@xxxxxxxxxxx> wrote in message
news:1147413633.569854.232010@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
i'm a newbie studying php.

i was into array part on tutorial and it says

i'll get an array having keys that from member variable's name

by converting an object to array.

i guessed "i can get public members but not protected, private, static
members"
(just like i got error if i try to access protected, private members
outside of object)

then i wrote a simple code to see how's it going.

################## code #######################
<?php
// for testing, each member of public, protected, private, static
CLASS test {
public $a = 'a';
protected $b = 'b';
private $c = 'c';
static $d = 'd';
}

//converting an object to array
$a = (array)new test();

var_dump($a);
echo '<br>';
/*let's see how it works (it threw not static member cuz it's not in
the object as i guessed. but it prints all other members including
public, protected, private eventhough i called this func outside of
object)*/

//i wanted to try to access by another way and it works too.
foreach($a as $i => $j)
echo "\$a : '$i' => '$j'<br>\n";

//i tryed to access by the key i saw on result. but it doesn't work at
all.
echo $a[' test c'] . "<br>\n";
?>

################## output #######################
array(3) {
["a"]=>
string(1) "a"
[" * b"]=>
string(1) "b"
[" test c"]=>
string(1) "c"
}
<br>$a : 'a' => 'a'<br>
$a : ' * b' => 'b'<br>
$a : ' test c' => 'c'<br>
<br>

#################################################


if i try to access protected, private members directly outside of the
object, i'll get an error.

but by convering the object to array, i can get all member variables.

is it right way? then what about the visibility. i think i can be a
problem.

Is it right way to access object members?(by converting to
array)<<----------------------------- Q1.

You're not accessing the members of the object anymore. It's an array, not
an object. The structure and values of the array are casted from an object,
but it's still an array and arrays have no restrictions like private or
protected. The answer simply to everything is that once you cast an object
to an array, the whole object context is thrown away and you are dealing
with an array. So you are really not accessing protected members of object
'cos it is not the object any longer.

anyway i tried to access by typing the key i saw on output ' * b' , '
test c', it didn't work.

while with the key variables i got from 'foreach', it worked.

i think i made a mistake on making the keys.

so

Can anyone explain me what's the problem on accessing by key i
typed?<<------------------Q2.

That's a difficult question. I see nothing wrong in it. Does $a['a'] work
either?

--
"ohjelmoija on organismi joka muuttaa kofeiinia koodiksi" -lpk
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