Re: preg_replace backreference value as a key to array
- From: "Chung Leong" <chernyshevsky@xxxxxxxxxxx>
- Date: 14 Sep 2006 13:28:59 -0700
Dave wrote:
Hi,
This is an interesting problem I'm faced with. I have been trying all sorts
of functions to fix it and my last resort is to ask you guys and girls.
I have an array:
$arr([3]=>"aaa",[104]=>"bbb",[345]=>"ccc",[n]=>"etc");
$html='<html>....<a href="page.php?var=3">3</a><a
href="page.php?var=345">345</a> ...<a
href="page.php?var=n">n</a>...</html>';
I'm trying to get a value from URLs in HTML and use it as a key to output
the value of $arr.
i.e. matching the: /page.php?var=(345)/ will output: "ccc";
Here is what I've tried but can't quite get there:
$html=preg_replace('/(href="page\.php\?)(var=)([0-9]+)/si','\\1var=' .
eval('\$c=\'\3\'; return \$c;'),$html);
Outputs the matched var: i.e. 345, but:
$html=preg_replace('/(href="page\.php\?)(var=)([0-9]+)/si','\\1var=' .
eval('\$c=\'\3\'; return \$arr[\$c];'),$html);
Won't output anything.
I tried to see if the backreferencfe value is really what it seems
(integer), but when I do:
$html=preg_replace('/(href="page\.php\?)(var=)([0-9]+)/si','\\1var=' .
eval('\$c=\'\3\'; \$c=gettype(\$c); return \$c;'),$html);
it shows it's a string. If I try: \$c*1, outputs is 0. If I try
settype(\$c,"integer"), the output again is 0.
Another strange thing. This: "return \$c;" returns the 345, but return
strlen(\$c); returns 2.
Please, save me from this madness! :)
Read the following:
http://fi.php.net/manual/en/function.parse-url.php
http://fi.php.net/manual/en/function.parse-str.php
.
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