Re: receive value $_POST

Well, I just use the commend

printf("%s ",%L);


And, my question is changed! I find out $L=$_POST['list']; can get a
list of numbers.

And another problem is,
Let's assume that $L=1,2,3
There's a table such as

A B
11 1
12 2
13 3
14 4
15 5
16 6

Then,

$sql="select A
FROM TABLE
WHERE B in ($L)
";

can be used. After that, How can I save 11,12,13 for one variable?
my thought was,

$result= mssql_query($sql) or die();

while ($row = mssql_fetch_array($result))
{
$veh = $veh+","+$row[0]; }

But it doesn't work.....
Help me...
thx.



Peter van Schie wrote:
kirke schreef:
oops, it was my mistake, I used square brackets. but still cannot
receive whole list of numbers. Get only first number(before first
comma)..


Hi kirke,

Maybe a stupid question, but how do you check the value of $L?
You said you're using:

$L=$_POST["list"];

What's the output of:

echo $L;

Or just do something like:

print_r($_POST);

to check the contents of the $_POST array.

Peter.

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