Re: Validate variables w/out empty
- From: "Rik Wasmus" <luiheidsgoeroe@xxxxxxxxxxx>
- Date: Wed, 31 Oct 2007 23:08:03 +0100
On Wed, 31 Oct 2007 23:01:45 +0100, pgt <pgtnot@xxxxxxxxx> wrote:
I have a working couple of pages (form submits 2 variables to the second
page using GET).
page1 has two dropdowns (generated from MySQL db).
page2 retrieves info from the database accordingly, depending on the passed
variables. Works fine.
I need to ensure that the user has actually selected both variables on page1
from each of the drop down options on page1.
empty() seems unable to do this because the default drop down options are
"Select one", "Select the other".
so on page2, if the user has NOT made any choices:
echo "Values passed to GET method:<br />\n";
reset ($_GET);
while (list ($key, $val) = each ($_GET)) {
echo "$key => $val<br />\n";
}
gives me:
Select one
Select the other
I can not see how to use empty() or isset() to resolve this, so...
Any ideas how to ensure the user has selected something from both options
(without javascript)?
I couldn't find anything in the manual but assume I'm looking in all the
wrong places for this.
Give the option a value 0 (well, it's more transparant/reliably checked then for the string 'Select one', and check if(!isset($_GET['option1']) || $_GET['option1'] = 0) echo 'Please select an option.';
Or you could 'whitelist' options. So you have an array of possible options, and check:
$array = array(...);
if(!isset($_GET['option1']) || !in_array($_GET['option1'],$array)) echo 'Please select.';
--
Rik Wasmus
.
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