Else If
- From: sales@xxxxxxxxxxxxxxxxxx
- Date: Fri, 30 Nov 2007 08:07:42 -0800 (PST)
Am trying Else-If but encounter a problem (newbie question, sorry)
Step 1 - Create selection of companies ordered by a priority number.
$query = "SELECT company, priority FROM foo1 WHERE foo2 AND priority
IN
('0', '1', '2') ORDER BY priority";
$result = mysql_query($query) or die ('Error in query: $query . ' .
mysql_error());
while($row = mysql_fetch_object($result))
Step 2 - I want to output the data in differing table formats
depending upon each of the priority numbers - hence Else If. Am just
displaying the variable values below for simplicity.
{
$priority = $row['priority'];
$company = $row['company'];
if ($priority == '0')
{
echo $company;
echo $priority;
}
elseif ($priority == '1')
{
echo $company;
echo $priority;
}
elseif ($priority == '2')
{
echo $company;
echo $priority;
}
}
The ElseIf however does not recognise if $priority equals either 1 or
2, even though it does, and it outputs only the condition for if
($priority == '0')
What am I doing wrong?????
Thanks
Alec
.
- Follow-Ups:
- Re: Else If
- From: Rik Wasmus
- Re: Else If
- Prev by Date: Re: Hard time with a regex...
- Next by Date: Re: Joomla?
- Previous by thread: Re: Hard time with a regex...
- Next by thread: Re: Else If
- Index(es):
Relevant Pages
|