Re: How to visualize network

On 19 Jan., 20:57, The Natural Philosopher <a...@xxx> wrote:
itschy wrote:
On 19 Jan., 17:19, The Natural Philosopher <a...@xxx> wrote:
itschy wrote:
On 18 Jan., 23:31, Jensen Somers <jensen.som...@xxxxxxxxx> wrote:
PHP has support to create images, so my guess is - if I understand the
problem correctly - you'll just need to find a way to draw dots and
lines, making them thicker depending on the weight they have.
Not quite.
You missed the part, where I mentiond that I do not have any
coordinates of the nodes. Thus I'cant just draw them, cause I don't
know where. :)
What I seek is some solution, which finds a representation according
to the information I have about the edges (that is, connected or not,
and if, what weight/line length do they have).
E.g.:
I have three nodes A,B,C and 3 connections a(A,B,3), b(B,C,4), c(A,C,
5) (each with infos about from_node, to_node and weight/length.
In this szenario, there are only two possible ways to draw that
network correctly:
5
A-----C B
3\ /4 3/ \4
B A-----C
5
And their rotations.
I try to find some tool/algorithm which is able to do this (and draw
it) in php.
Tough luck I guess... :(
itschy
Didn't they teach you basic geometry at school?

three nodes with three paths, defines a unique shape, which is constant.
It can be rotated and mirrored,without violating the original
definition, but the shape remains constant.

To plot it, simply assume one point (A) is at 0,0, the next one - say
'B' is at the correct distance along the X axis, so in your case its
co-ordinates are 3,0.

Solving the position of the third point C involves solving a pair of
simultaneous quadratic equations. Cf Pythagoras and the dropping of
perpendiculars.

Namely:-

Cx^2+Cy^2=(5)^2
(3-Cx)^2 +Cy^2=(4)^2

Now there are either two, or none, solutions for Cy as there always are
for quadratics. One solution is the mirror of the other.

Now go solve it.

Its your homework, not mine.

Thanks for teaching me.
Now, have you read anything I wrote?
In short words i will summarize:
0. They did not only teach me basic geometry in school, but also
analytical geometry, graph theory and such in university.
1. I try to find an EXISTING solution not write my own.
2. Jensen Somers misunderstood my initial post, so I clarified, what
kind of solution I seek. I described to him exactly what you did to me
(in a visual way).
3. I know well how to do it, I wanted to know if it was done before
(because with all the drwaing stuff it is not worth it to implement it
by myself)
4. Your answer is still welcome, maybe someone searching and finding
this thread can use it. but next time please don't assume everyone
else is stupid! :)

I don't assume. I go on the evidence.

Maths packages exist.
Graphics packages exists.
The mathematics of quadratics is well known.

So all it needs s an unstupid unlazy person to put them all together.

Php doesn't have a package to calculate the net loss in weight of a
rutting elephant after sex, either.

If you want soenmthing that obscure, write it.

So, the answer to my question would be:
"No, it doesn't exist"
All I wanted to know...

PS: I have to admit I never wondered about that elephant thing ;)
.

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