Re: Question about 'sizeof'
- From: Jerry Stuckle <jstucklex@xxxxxxxxxxxxx>
- Date: Thu, 08 May 2008 16:27:13 -0400
SM wrote:
On May 8, 12:31 pm, Piotr <s...@xxxxxxxxxxxxxx> wrote:SM wrote:On May 8, 11:50 am, SM <servandomont...@xxxxxxxxx> wrote::)On May 8, 11:42 am, Piotr <s...@xxxxxxxxxxxxxx> wrote:Maybe i should open a new post for this one, but here it goes:I don't need the length of the string , just the actual variable. ButForgot about one small detail:$thumb = 1;You should use variable variable:
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1
$item_total = sizeof($item);
output: Nothing!
How do i pass a variable to the 'sizeof' function?
$item_total = sizeof($$item);
Mark double $$
This is true in any situation, not only with sizeof
$item = 'thumbs_cat_' . $thumb; //this outputs a string:
---------^ loose the '$';
best regards
Piotr N
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!
Heres the final code:
$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($$item);
Thanks again
Marco
I'm stock! When i want to reference that variable in a echo statment,
it does't work. Any suggestions?
Thanks
<li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
$category_this; ?>"><img src="images/<?php echo($$item[$i]);?>"
alt="" /></a></li>
It should look like this. Mark the { and }
echo ${$item[$i]};
As a side note, is this really best way to access needed data this way ?
Cant you keep original values in the array instead of the variable names ?
best regards
Piotr N
I've tried it, It doesn't work. When i look at the source code, i see
an empty string:
<img src="images/" alt="" />
Here's what im trying to do:
-From a list, the user selects the category of discography (either
original, compilation, tributes, other)
-Each type of discography is associated with an array that contains
the name of the cd covers.
-Then i show a thumbnail (using a loop) of all the cd covers.
my arrays look like this (one for each category of discography)
$thumbs_cat_1 = array('moonlight.jpg'', shadow.jpg', 'luna.jpg');
$thumbs_cat_2 = array(...);
$thumbs_cat_3 = array(...);
$thumbs_cat_4 = array(...);
Then i create the thumbs like this:
for($i=0; ...){
...<img src="images/discography/thumbs/<?php echo $thumbs_cat_1[$i]; ?
" alt="" />}
All of this works perfectly for the first array.
That's why, i think, i need a variable that contains the selection
from the user (the category of discography) so i can select values
from the correct array.
I do it like this:
$cat = $_GET['cat']; //output: 1
$sel_array = 'thumbs_cat_' . $cat;//create the string: thumbs_cat_1
Then i create the thumbs like this:
for($i=0; ...){
...<img src="images/discography/thumbs/<?php echo ${$sel_array[$i]}; ?
" alt="" />}
... and so on
You think my code makes sense? Maybe i'm doing it wrong.
The last part is were im stock...
Any ideas what's wrong?
Thanks again
Marco
Why go to all that trouble. Just use a two dimensional array, i.e.
$thumb_cats = array();
$thumb_cats[] = array('moonlight.jpg'', shadow.jpg', 'luna.jpg');
$thumb_cats[] = array(...);
$thumb_cats[] = array(...);
$thumb_cats[] = array(...);
$thumb_cats[] = array(...);
<img src="images/discography/thumbs/<?php echo $thumb_cats[$sel][$i];?>"
alt="" />
Much cleaner.
--
==================
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Jerry Stuckle
JDS Computer Training Corp.
jstucklex@xxxxxxxxxxxxx
==================
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