Re: Problem in the output of an array

From: John (john_at_coggeshall.org)
Date: 11/30/03 

To: Robert Cummings <robert@interjinn.com>
Date: Sat, 29 Nov 2003 19:25:44 -0700

> $result = eval( 'return $array'.$test.';' );

Um...

echo $array[$dim1][$dim2][$dim3][$dim4];

eval == evil. I can't think of a single legimiate reason why you'd want/need
to make a string "[$dim1]...." first, and if you have to I'd suspect that
something is very wrong with the way you are writing your script.

Feel free to prove me wrong, though :)

John

 

Robert Cummings writes:

> On Sat, 2003-11-29 at 19:47, Robert Cummings wrote:
>> On Sat, 2003-11-29 at 19:29, sophie@sitadelle.com wrote:
>> > I'm soory but your code doesn't make me understand what you want to do...
>> > Be more precise, it will help you to get some help
>> >
>> > > I have this code, I would like, if this could be done
>> > >
>> > > <?
>> > > $array['dim1']['dim2']['dim3'][3] = "value";
>> > >
>> > > $dim1 = 'dim1';
>> > > $dim2 = 'dim2';
>> > > $dim3 = 'dim3';
>> > > $dim4 = 3;
>> > >
>> > > $test = "[$dim1][$dim2][$dim3][$dim4]";
>> > > $result = "$array$test";
>> > >
>> > > echo $result;
>> > > ?>
>> > >
>> > > The output is : Array[dim1][dim2][dim3][3]
>> > >
>> > > I need that the output was: value
>>
>
> Ignore my last answer, I read your problem wrong. Answer below:
>
> <?
> $array['dim1']['dim2']['dim3'][3] = "value";
>
> $dim1 = 'dim1';
> $dim2 = 'dim2';
> $dim3 = 'dim3';
> $dim4 = 3;
>
> $test = '[$dim1][$dim2][$dim3][$dim4]';
>
> $result = eval( 'return $array'.$test.';' );
> echo $result;
> ?>
>
> HTH,
> Rob.
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