Re: [PHP] Help wtih a query?
- From: prthomp@xxxxxxxx (Philip Thompson)
- Date: Tue, 30 Jan 2007 18:53:32 -0600
On Jan 30, 2007, at 4:33 PM, Skip Evans wrote:
Hey all,
I have the following query:
$sql="SELECT count(*) AS count,votes.storyID,stories.title,stories.storyID as sID,stories.approved, stories.story,stories.userID, fname, lname
FROM `bsp_story_votes` as votes, bsp_story_stories AS stories, users AS usr
WHERE votes.storyID=stories.storyID AND stories.userID=usr.id AND stories.contestID=$contestID
GROUP BY votes.storyID
ORDER BY stories.approved,count DESC, sID ASC LIMIT $b_recno,$recs";
How would this need to be changed so that it would return rows for the members of the bsp_story_stories table that do not have records in the bsp_story_votes table?
Is that what the left/right joins do???
Thanks!
Skip
This may be closer to what you're wanting...
<query>
SELECT count(stories.*) AS count, votes.storyID, stories.title, stories.storyID AS sID, stories.approved, stories.story, stories.userID, fname, lname
FROM bsp_story_votes AS votes LEFT JOIN (bsp_story_stories AS stories ON votes.storyID = stories.storyID) INNER JOIN users AS usr ON stories.userID = usr.id
WHERE stories.contestID=$contestID
GROUP BY votes.storyID
ORDER BY stories.approved, count DESC, sID ASC LIMIT $b_recno, $recs
</query>
If that doesn't work, you may try changing the LEFT to RIGHT. I probably screwed it up, but that's closer to how JOINs work. I'm not sure if the GROUP BY will work with this query either??? I thought you had to use HAVING with a GROUP BY? Refer to the M*SQL manual.
Now that think about it... I don't know if you can have a 'count()' in with that query. If it doesn't work, you may try pulling count() out and just using m*sql_num_rows() afterwards to get the count. Hope that helps!
~Philip
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- From: Skip Evans
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