Re: [PHP] WHERE problem
- From: ceo@xxxxxxxxx ("Richard Lynch")
- Date: Tue, 20 Feb 2007 16:29:00 -0600 (CST)
On Mon, February 19, 2007 2:32 pm, Bruce Cowin wrote:
I'd like to think I understood code a little better than this, butMike Shanley <thebarmy@xxxxxxxxxxxxxxxxx> 20/02/2007 9:23:08 a.m.
I've
got a problem with my WHERE...
I know it's the WHERE because I get a good result when I leave it out.
And the random function is also working... I honestly can't figure it
out. Thanks in advance for help with this laughable prob.
---------------------------
// How many are there?
$result = mysql_query("SELECT count(*) FROM fortunes");
$max = mysql_result($result, 0);
// Get randomized!... the moderated way...
$randi = mt_rand(1, $max-1);
$q = "SELECT text FROM fortunes WHERE index = '$randi'";
$choose = mysql_query($q);
$chosen1 = mysql_fetch_array($choose);
Are you certain that your 'index' field runs from 1 to $max-1 and you
will never DELETE a fortune leaving a hole in your 'index' values?...
Unless you really really really need the quality of the Merseinne
Twister random generator, you could just do:
SELECT text FROM fortunes ORDER BY rand() LIMIT 1
(Or is it random() in MySQL? I always confuse mysql/pg random
function name...)
Also, 'text' is a field type in SQL, so you may need:
SELECT `text` to make it not be reserved word.
Ditto for index -> `index` perhaps.
// Ready to ship...
$fortune = '<span class="quotecyc">"' . $chosen1[0] .
'"<br/>-Omniversalism.com</span>';
mysql_close();
As a matter of Code Style, you MAY want to consider doing:
$chosen = mysql_result($choose, 0, 0);
instead of creating a 1-element array and then accessing element 0 of
that array.
Some developers prefer to always do their PHP/mysql "the same"
Others prefer to make it clear when they are getting a singleton
database result, by using a different pattern of code.
--
Some people have a "gift" link here.
Know what I want?
I want you to buy a CD from some starving artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?
.
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